Given the system of equations below, \[x=?\]
\[y+3x=9\]
\[2x−\frac{1}{3}y=6\]
The first step in answering this question is to rearrange one of the given equations so that it is expressed in terms of y:
\[y+3x=9\]
\[y=−3x+9\]
To solve for x, the next step is to plug \[−3x+9\] in for y in the second equation:
\[2x-\frac{1}{3}(9-3x)=9\]
\[2x−3+x=6\]
\[3x=6+3\]
\[x=3 \]