Total cost of typewriter \[= (1200 + 200) = 1400\]
S.P. \[= 1680\]
Profit \[= (1680 – 1400) = 280\]
\[\therefore\] Profit \[\% = \frac{280}{1400}\times100 = 20\%\]
Minimum cost price
\[= 150 × 15 = 2250\]
Maximum selling price
\[= 350 × 15 = 5250\]
Gain
\[= 5250 – 2250 = Rs.3000\]
[\[150\] being the lowest & \[350\] being the highest price]
Let the C.P. of the article be Rs. \[x\] .
According to the question,
\[425 – x = x – 355\]
\[\implies 2 x = 425 + 355 = 780\]
\[\implies x = \frac{780}{2}\]
\[= Rs. 390\]
Let the C.P. of the article be \[Rs.x\]
According to the question,
\[78 – x = 2 (69– x )\]
\[\implies 78 – x = 138 – 2 x\]
\[\implies 2 x – x = 138 – 78 \]
\[\implies x = Rs. 60\]
Let the C.P. of one orange \[= 1\]
C.P. of \[40\] oranges \[= Rs.40\] and
S.P. of \[40\] oranges \[= Rs.50\]
\[\therefore Profit = (50 – 40) = Rs.10\]
\[\therefore \ Profit \ \% = ́\frac{10}{40}\times100\]
\[= 25\%\]
Let the CP of each pen be \[Rs.1\].
\[\therefore\] CP of \[8\] pens \[= Rs.8\]
SP of \[8\] pens \[= Rs.12\]
\[\therefore \ Gain \ \% = \frac{4}{8} ×100\]
\[= 50\%\]
C.P. of cycle \[= Rs. 1000\]
Its S.P.\[ = Rs. 1200 \]
Profit \[= Rs. (1200 – 1000)\]
\[= Rs. 200\]
\[\therefore\] Profit percent \[= \frac{200}{1000}\times100\]
\[= 20\%\]
C.P. \[= 12\]
S.P. \[= 12 × 1.25 = 15\]
Total Profit \[= 15 – 12 = 3\]
\[\therefore Gain \ \% = ́ \frac{3}{12}\times100\]
\[= 25\%\]
Total C.P. \[= Rs.32\]
Total S.P. \[= Rs.(18+2) = Rs.20\]
Loss \[= Rs.(32-20) = Rs.12\]
\[\therefore\] Loss per cent \[\frac{12}{32}\times100\]
\[= 37.5\%\]
Let the CP of each ball \[= x\] . Then,
clearly the cost price of \[(17 – 5)\] balls \[= 720\]
i.e., \[12 x = Rs.720\]
\[\implies x = 60\] i.e. \[Rs.60\]
Let the vendor buy \[20\] (LCM of \[5\] and \[4\]) bananas.
\[\therefore\] CP of \[20\] bananas \[= 4\]
SP of \[20\] bananas \[= 5\]
\[Gain \ \% = \frac{5-4}{4}\times100\]
\[=25\%\]