Practice Percentage

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What percentage is equivalent to \[\frac{1}{2}\] ?

\[20\%\]

\[30\%\]

\[40\%\]

\[50\%\]

\[\frac{1}{2}\times100=50\%\]

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What fraction is \[50\%\] ?

\[\frac{1}{2}\]

\[\frac{1}{3}\]

\[\frac{1}{4}\]

\[\frac{1}{5}\]

\[50\%=\frac{50}{100}=\frac{1}{2}\]

3 / 20

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What is \[25\%\] of \[1000\] ?

100

250

400

500

\[25\%\ of\ 1000=\frac{25\times1000}{100}=250\]

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Find a number whose \[5\%\] is \[40\] ?

200

400

600

800

Let the required number be \[x\].

Then \[5\% \ of\ x = 80\]

\[\Rightarrow\frac{5}{100}\times x=40\]

\[\Rightarrow x=\frac{\left(40\times100\right)}{5}\]

\[=800\]

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What percent of \[25kg\] is \[5kg\] ?

\[10\%\]

\[20\%\]

\[30\%\]

\[40\%\]

Let \[x\%\] of \[25kg\] be \[5kg\].

Then, \[\frac{x\times25}{100}=5.\]

\[\Rightarrow x=\frac{5\times100}{25}=\frac{100}{5}=20\]

Hence, \[5kg\] is\[ 20\%\] of \[25kg\].

6 / 20

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\[30\%\] of \[x\] is \[72\]. The value of \[x\] is:

216

240

480

640

\[30\% \ of \ x=72\]

\[\therefore x=\frac{\left(72\times100\right)}{30}\]

\[=240\]

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If \[10\% \ of \ A = 20\% \ of \ B,\] then \[\frac{A}{B}=?\]

\[\frac{1}{2}\]

\[\frac{2}{1}\]

\[\frac{1}{4}\]

\[\frac{4}{1}\]

\[10\%\ of\ A=20\%\ of\ B\]

\[\therefore\frac{\left(10\times\ A\right)}{100}=\frac{\left(20\times\ B\right)}{100}\]

\[\Rightarrow10A=20B\]

\[\Rightarrow\frac{A}{B}=\frac{20}{10}\]

\[=\frac{2}{1}\]

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What is \[20\% \ of \ 25\% \ of \ 300?\]

150

\[20\%\ of\ 25\%\ of\ 300\]

\[=\frac{20}{100}\times\frac{25}{100}\times300\]

\[=\frac{1}{5}\times\frac{1}{4}\times300\]

\[=15\]

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If \[p\%\ of\ p\%\ =36,\] then the value of \[p\] is

\[p\%\ of\ p\%\ =36\]

\[\therefore\frac{\left(p\times p\right)}{100}=36\]

\[\Rightarrow p^2=36\times100\]

\[\Rightarrow p=\sqrt{36\times100}\]

\[=60\]

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\[\frac{1}{3}\] is what \[\% \ of\] \[\frac{2}{3}?\]

\[50\%\]

\[100\%\]

\[150\%\]

\[200\%\]

Let \[x\%\ of\ \frac{1}{3}=\frac{2}{3},\] then

\[\frac{\left(x\times\frac{1}{3}\right)}{100}=\frac{2}{3}\]

\[\Rightarrow x=\frac{\left(\frac{2}{3}\times100\right)}{\frac{1}{3}}\]

\[\Rightarrow x=\frac{2}{3}\times\frac{3}{1}\times100\]

\[\Rightarrow x=2\times100\]

\[\therefore x=200\%\]

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Half of \[1\] percent, written as a decimal, is

0.2

0.5

0.02

0.005

Half of \[1\%=\frac{1}{100}\times\frac{1}{2}\]

\[=\frac{1}{200}\]

\[=0.005\]

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In a school, \[60\%\] of the students are interested in playing cricket. If the total number of students is \[2000\], then how many of them play cricket?

600

800

1000

1200

\[60\%\ of\ 2000\] students

\[=\frac{\left(60\times2000\right)}{100}\]

\[=1200\]

Therefore \[1200\] students are interested in playing cricket.

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In a class of \[50\] students, \[10\] students failed in Maths. What is the percentage of students who passed in Maths?

\[20\%\]

\[40\%\]

\[60\%\]

\[80\%\]

According to the question,

\[10\] students failed in Maths,

\[\therefore\] number of students who passed in Maths \[= 50-10=40\]

So, the percentage of students who passed in Maths

\[=\left(\frac{40}{50}\times100\right)\%\]

\[=80\%\]

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In a school of \[1000\] students, \[40\%\] students are boys and \[60\%\] students are girls. What is the ratio of boys to girls ?

\[\frac{1}{3}\]

\[\frac{2}{3}\]

\[\frac{3}{4}\]

\[\frac{5}{3}\]

Total number of students \[= 1000\]

Number of boys \[=40\%\ of\ 1000\]

\[=\frac{\left(40\times1000\right)}{100}\]

\[=400.\]

Similarly, Number of girls \[=60\%\ of\ 1000\]

\[=\frac{\left(60\times1000\right)}{100}\]

\[=600.\]

\[\therefore\] ratio of boys to girls \[=\frac{400}{600}=\frac{4}{6}=\frac{2}{3}\]

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The monthly income of Mohan is \[Rs.30000/-.\] If Rakesh earns \[50\%\] more than Mohan, then find the monthly income of Rakesh?

\[Rs.35,000/-\]

\[Rs.40,000/-\]

\[Rs.45,000/-\]

\[Rs.50,000/-\]

Monthly income of Mohan \[= Rs.30,000/-.\]

According to the question,

Monthly income of Rakesh \[= 150\% \ of \ \] Mohan's income.

\[=150\%\ of\ Rs.30,000/-\]

\[=\frac{\left(150\times3000\right)}{100}\]

\[=45000\]

\[\therefore\] Montlhy income of Rakesh is \[Rs.45,000/-\]

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Rahul earns \[Rs.20,000/-\] per month and spends \[20\%\] of his monthly income. How much does he save each month?

\[Rs.12,000/-\]

\[Rs.14,000/-\]

\[Rs.16,000/-\]

\[Rs.18,000/-\]

According to the question,

Monthly income of Rahul \[= Rs.20,000/-\]

Monthly expenditure of Rahul \[= 20\% \ of \ Rs.20,000/-\]

\[=20\%\ of\ 20000\]

\[=\frac{\left(20\times2000\right)}{100}\]

\[=4000\]

\[\therefore\] Monthly savings of Rahul will be,

\[Rs.20,000 - Rs.4,000/-\]

\[=Rs.16,000/-\]

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If three-fifth of sixty percent of a number is \[36\], the number is

100

Let the number be \[x\] .

\[\therefore\frac{3}{5}\times\frac{60}{100}\times x=36\]

\[\Rightarrow x=\frac{36\times5\times100}{3\times60}\]

\[=100\]

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\[1\% \ of \ 1\% \ of \ 25\% \ of \ 1000\] is

0.25

0.025

0.0025

\[1\%\ of\ 1\%\ of\ 25\%\ of\ 1000\]

\[=\frac{1}{100}\times\frac{1}{100}\times\frac{25}{100}\times1000\]

\[=\frac{\left(25\times10\right)}{100\times100}\]

\[=\frac{25}{1000}\]

\[=0.025\]

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Deepak bought a bicycle at \[Rs.5,000/-\]. He then sold it to his friend by making \[20\%\] profit. At what price did he sell the bicycle?

\[Rs.5,400/-\]

\[Rs.5,600/-\]

\[Rs.5,800/-\]

\[Rs.6,000/-\]

Deepak purchased the bicycle in \[Rs.5,000/-\]

He made a profit of \[20\%,\]

that means he finally got \[120\% \ of \ Rs.5,000/-\]

\[=120\%\ of\ 5000\]

\[=\frac{\left(120\times5000\right)}{100}\]

\[=6000\]

Thus he sold the bicycle at \[Rs.6,000/-\]

20 / 20

Find the number if it is \[20\%\ of\ 25\%\ of\ 100\].

Let the number be \[x\], then

\[x=20\%\ of\ 25\%\ of\ 100\]

\[=\frac{20}{100}\times\frac{25}{100}\times100\]

\[=5\]